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2s^2-11s-215=0
a = 2; b = -11; c = -215;
Δ = b2-4ac
Δ = -112-4·2·(-215)
Δ = 1841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{1841}}{2*2}=\frac{11-\sqrt{1841}}{4} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{1841}}{2*2}=\frac{11+\sqrt{1841}}{4} $
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